Question

18a^2x^2-32 factorise

Answer 1

Answer :

Now,

18a²x² - 32

= 2 (9a²x² - 16)

= 2 {(3ax)² - 4²}

= 2 (3ax + 4) (3ax - 4),

[using the identity
a² - b² = (a + b) (a - b)]

which is the required factorization.

#MarkAsBrainliest

Answer 2

Heya !!!

18A²X² - 32

2 × 9A²X² - 2 × 16

2 ( 9A²X² - 16)

2{ ( 3AX)² - (4)² }


We know that,


( A )² - (B)² = ( A+B) (A-B)



Therefore,


2 { ( 3AX)² - (4)² }

=> 2{ ( 3AX+4) ( 3AX-4) }

HOPE IT WILL HELP YOU...... :-)