Question

18g of glucose is added to 178.2g of water. The vapour pressure of water for this aqueous solution at 100 degree Celsius is?

Answer 1

Molar mass of water = 18g.

For 178.2g of H2,nA= 9.9. 0.1/ 0.1+ 9.9= 0.01. Molar mass of glucuse = 180g 0.99. For 18g , nB =0.1. For lowering of vapour pressure. p= p0*A=P0A (1-x B)= 760. ( 1-0.01). P =760- 7.6. P=752.4. Hope this helps u