Chemistry, asked by yahya6492, 6 hours ago


18g of glucose is dissolved in 180g of water. The relative lowering of vapour pressure
A.1
B. 1.8
C. 0.01
D. 0.001​

Answers

Answered by nikitasharma2961
1

Answer:

0.001

Explanation:

Vapor Pressure lowering is governed by Raoult's law, which basically states:

Pn=(Xn)×Po

were Pn is the new vapor pressure, Xn is the mole faction of the solvent, and Po is the pure solvent vapor pressure.

I think the relative lowering would be(1−PnPo), which is (1−Xn)

Xn=moles of watertotal moles

Xn=1010.1=0.99009901

Relative Lowering:

(1−0.99009901)=0.00990099=0.01

Answered by touseefshigree
1

Answer:0.1

Explanation:0.1÷10.1=0.01

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