Question

18g of glucose is dissolved in 90 gof water. The relative lowering of vapour pressure to​

Answer 1

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Answer 2

Explanation:

Molecular mass of water= 2×1+1×16=18g

=2×1+1×16=18g

For 90g178.2g water n

A

=5

Molecular mass of glucose 6×12+12×1+6×16=180g

For 18g glucose n

B

=0.1

Now, X

B

=

0.1+5

0.1

=0.0196 ~0.02

Answer provided by Gauthmath