Question

18g of glucose(molar mass 180g/mol)is present in 500cm3 of its aquous solution what is the molarity of the solution​

Answer 1

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Answer 2

The molarity of glucose solution is 0.2 M

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of glucose = 18 g

Molar mass of glucose = 180 g/mol

Volume of solution = $500cm^3=500mL$     (Conversion factor:  $1cm^3=1mL$ )

Putting values in above equation, we get:

$\text{Molarity of glucose solution}=\frac{18\times 1000}{180\times 500}\\\\\text{Molarity of glucose solution}=0.2M$

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