Question

18gm glocouse present in 1lit water. what is the molar unit?​

Answer 1

Answer:

Molarity = No. of moles of a solute/1L of solution

Moles of glucose = 18g/(180g/mol) = 0.1 mole.

Since the density of water is about 1g/ml, the 500g of water = 500ml.

Hence molarity of glucose = 0.1mole/500ml = (0.10mole x 1000ml)/500ml = 0.2 mol/L

Answer 2

Molarity = No. of moles of a solute/1L of solution

Moles of glucose = 18g/(180g/mol) = 0.1 mole.

Since the density of water is about 1g/ml, the 500g of water = 500ml.

Hence molarity of glucose = 0.1mole/500ml = (0.10mole x 1000ml)/500ml = 0.2 mol/L