Question

18gm of glucose is present in the 90gm of water.calculate the mole fraction in glucose solution​

Answer 1

Given :

Mass of glucose = 18g

Mass of water = 90g

To Find :

Mole fraction of glucose in solution.

Solution :

❒ Mole fraction : Ratio of number of moles of one component to the total number of moles of all components.

Symbol : x

Effect of temperature : No effect

Formula :

$\bigstar\:\underline{\boxed{\bf{\gray{X_A=\dfrac{N_A}{N_A+N_B}}}}}$

First of all we need to find number of moles of glucose and water.

Glucose : $\sf{N_G}$ = 18/180 = 0.1

• Molar mass of glucose = 180

Water : $\sf{N_W}$ = 90/18 = 5

• Molar mass of water = 18

By substituting the values;

$\sf:\implies\:X_G=\dfrac{N_G}{N_G+N_W}$

$\sf:\implies\:X_G=\dfrac{0.1}{0.1+5}$

$\sf:\implies\:X_G=\dfrac{0.1}{5.1}$

$:\implies\:\underline{\boxed{\bf{\purple{X_G=0.02}}}}$

Answer 2

Answer:

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