Question

(18r⁵+36r⁴+27r³) ÷ 9r

Answer 1

Step-by-step explanation:

(18r^5+36^4+27r^3)/9r

9r(2r^4+4r^3+3r^2)/9r

2r^4+4r^3+3r^2

Answer 2

Answer:

Required answer is ${r}^{2}(2 {r}^{2} + 4r + 3)$

Step-by-step explanation:

Given two terms are

$(18 {r}^{5} + 36 {r}^{4} + 27 {r}^{3} )$ and 9r

We want to divide $(18 {r}^{5} + 36 {r}^{4} + 27 {r}^{3} )$ by 9r.

Now question is what is Division?

We know,

Division is the mathematical process of finding out how many times one number is contained in another.

Divide a by b = a÷b $= \frac{a}{b}$

By one example, we can understand this concept.

$= 20 \div 5 \\ = \frac{20}{5} \\ = 4$

Now,

$(18 {r}^{5} + 36 {r}^{4} + 27 {r}^{3} ) \div 9r \\ = \frac{(18 {r}^{5} + 36 {r}^{4} + 27 {r}^{3} )}{9r} \\ = \frac{9 {r}^{3}(2 {r}^{2} + 4r + 3) }{9r} \\ = \frac{ {r}^{2}(2 {r}^{2} + 4r + 3) }{1} \\ = {r}^{2}(2 {r}^{2} + 4r + 3)$

Division related two more questions:

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