(18r5+36r4+27r3)÷9r divide
Answers
Answer:
STEP
1
:
Equation at the end of step 1
(((18•(r5))+(36•(r4)))+33r3)
————————————————————————————•r
9
STEP
2
:
Equation at the end of step
2
:
(((18•(r5))+(22•32r4))+33r3)
————————————————————————————•r
9
STEP
3
:
Equation at the end of step
3
:
(((2•32r5) + (22•32r4)) + 33r3)
——————————————————————————————— • r
9
STEP
4
:
18r5 + 36r4 + 27r3
Simplify ——————————————————
9
STEP
5
:
Pulling out like terms
5.1 Pull out like factors :
18r5 + 36r4 + 27r3 = 9r3 • (2r2 + 4r + 3)
Trying to factor by splitting the middle term
5.2 Factoring 2r2 + 4r + 3
The first term is, 2r2 its coefficient is 2 .
The middle term is, +4r its coefficient is 4 .
The last term, "the constant", is +3
Step-1 : Multiply the coefficient of the first term by the constant 2 • 3 = 6
Step-2 : Find two factors of 6 whose sum equals the coefficient of the middle term, which is 4 .
-6 + -1 = -7
-3 + -2 = -5
-2 + -3 = -5
-1 + -6 = -7
1 + 6 = 7
2 + 3 = 5
3 + 2 = 5
6 + 1 = 7
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step
5
:
r3 • (2r2 + 4r + 3) • r
STEP
6
:
Multiplying exponential expressions :
6.1 r3 multiplied by r1 = r(3 + 1) = r4
Final result :
r4 • (2r2 + 4r + 3)