Question

18th term of A.P √2,3√2,5√2​

Answer 1

here is your answer

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Answer 2

Answer:

Step-by-step explanation:

tn=a+[n-1]d

a=first term

n=n th term

d=common difference 3√2-1√2=2

t18=1√2+[18-1]2

t18=1√2+34

    =35√2