18th term of AP exceeds it's 12th term by 8 find the common difference
Answers
Answered by
15
Solution:-
Let a be the first term and d be the common difference of the given AP.
18th term of AP t₁₈ = a + 17d
12th term of AP t₁₂ = a + 11d
Given that the 18th term of an AP exceeds its 12th term by 8.
Therefore,
a + 17d = a + 11d + 8
17d - 11d = 8
6d = 8
d = 8/6
d = 4/3
Let a be the first term and d be the common difference of the given AP.
18th term of AP t₁₈ = a + 17d
12th term of AP t₁₂ = a + 11d
Given that the 18th term of an AP exceeds its 12th term by 8.
Therefore,
a + 17d = a + 11d + 8
17d - 11d = 8
6d = 8
d = 8/6
d = 4/3
Similar questions