18x +2 x cube - 12 x square
factorise
Answers
Answer:
Step-1 : Multiply the coefficient of the first term by the constant 1 • 9 = 9
Step-2 : Find two factors of 9 whose sum equals the coefficient of the middle term, which is -6 .
-9 + -1 = -10
-3 + -3 = -6 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and -3
x2 - 3x - 3x - 9
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-3)
Add up the last 2 terms, pulling out common factors :
3 • (x-3)
Step-5 : Add up the four terms of step 4 :
(x-3) • (x-3)
Which is the desired factorization
Answer:
((2 • (x3)) - (22•3x2)) + 18x = 0
(2x3 - (22•3x2)) + 18x = 0
Pull out like factors :
2x3 - 12x2 + 18x = 2x • (x2 - 6x + 9)
Factoring x2 - 6x + 9
The first term is, x2 its coefficient is 1 .
The middle term is, -6x its coefficient is -6 .
The last term, "the constant", is +9
Step-1 : Multiply the coefficient of the first term by the constant 1 • 9 = 9
Step-2 : Find two factors of 9 whose sum equals the coefficient of the middle term, which is -6 .
-9 + -1 = -10
-3 + -3 = -6 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and -3
x2 - 3x - 3x - 9
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-3)
Add up the last 2 terms, pulling out common factors :
3 • (x-3)
Step-5 : Add up the four terms of step 4 :
(x-3) • (x-3)
Which is the desired factorization