Question

18x +2 x cube - 12 x square
factorise ​

Answer 1

Answer:

Step-1 : Multiply the coefficient of the first term by the constant 1 • 9 = 9

Step-2 : Find two factors of 9 whose sum equals the coefficient of the middle term, which is -6 .

-9 + -1 = -10

-3 + -3 = -6 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and -3

x2 - 3x - 3x - 9

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-3)

Add up the last 2 terms, pulling out common factors :

3 • (x-3)

Step-5 : Add up the four terms of step 4 :

(x-3) • (x-3)

Which is the desired factorization

Answer 2

Answer:

((2 • (x3)) - (22•3x2)) + 18x = 0

(2x3 - (22•3x2)) + 18x = 0

Pull out like factors :

2x3 - 12x2 + 18x = 2x • (x2 - 6x + 9)

Factoring x2 - 6x + 9

The first term is, x2 its coefficient is 1 .

The middle term is, -6x its coefficient is -6 .

The last term, "the constant", is +9

Step-1 : Multiply the coefficient of the first term by the constant 1 • 9 = 9

Step-2 : Find two factors of 9 whose sum equals the coefficient of the middle term, which is -6 .

-9 + -1 = -10

-3 + -3 = -6 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and -3

x2 - 3x - 3x - 9

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-3)

Add up the last 2 terms, pulling out common factors :

3 • (x-3)

Step-5 : Add up the four terms of step 4 :

(x-3) • (x-3)

Which is the desired factorization