Question

18x +4x^2=22 find the value of x.

Answer 1

18x + 4x^2 = 22

4x^2 + 18x - 22 =0

2{2x^2 + 9x - 11} = 0

2x^2 + 9x - 11 = 0

2x^2 + 11x - 2x - 11 = 0

x(2x + 11) -1(2x + 11) = 0

(2x + 11) (x-1) = 0

2x + 11 = 0

2x = - 11

x = -11/2

or

x-1=0

x=1

Hope this helps you :)

Answer 2

Answer:

Step-by-step explanation:

First write it in correct quadratic equation

4x2+18x-22

Device it by 2

2x2+9x-11

By quadratic formula

-9+-root81+88÷4

-9+-13÷4

X=1,-5