Question

18x-[5x³+3x²-{2x²-(6-2x-x³)-5x³}-3x]​

Answer 1

Answer:

Given:-

Solve : 18x - [ 5x³ + 3x² - { 2x² - ( 6 - 2x - x³ ) - 5x³ } - 3x ].

To Find:-

The solution of the : 18x - [ 5x³ + 3x² - { 2x² - ( 6 - 2x - x³ ) - 5x³ } - 3x ].

Note:-

●》Here; we will start adding or subtracting ( if it can be ) from - Small bracket ( ), Next - Curly bracket { }, At Last - Big bracket [ ].

●》When terms inside the bracket can be calculated then we will open the bracket by multiplying the signs or number outside the bracket terms.

Solution:-

$\huge\red{18x - [ 5x³ + 3x² - { 2x² - ( 6 - 2x - x³ ) - 5x³ } - 3x ]}$

$\huge\red{ \ \ \ \ Their \ \ Solution = ?}$

☆ According to note first amd second point ( opening small bracket )~

▪︎$18x - [ 5x³ + 3x² - { 2x² - ( 6 - 2x - x³ ) - 5x³ } - 3x ]$

▪︎$18x - [ 5x³ + 3x² - { 2x² ( - 6 - × - 2x - × - x³ ) - 5x³ } - 3x ]$

☆ Negative × Negative = Positive, Negative × Positive = Negative, Positive × Negative = Negative~

▪︎$18x - [ 5x³ + 3x² - { 2x² - 6 + 2x + x³ - 5x³ } - 3x ]$

▪︎$18x - [ 5x³ + 3x² - { 2x² - 6 + 2x - 4x³ } - 3x ]$

☆ Now, opening the curly bracket~

▪︎$18x - [ 5x³ + 3x² { - 2x² - × - 6 - × + 2x - × - 4x³ } - 3x ]$

▪︎$18x - [ 5x³ + 3x² - 2x² + 6 - 2x + 4x³ - 3x ]$

☆ Taking common terms inside the bracket together~

▪︎$18x - [ 5x³ + 4x³ + 3x² - 2x² + 6 - 2x - 3x ]$

▪︎$18x - [ 9x³ + x² + 6 - 5x ]$

☆ Now, opening the big bracket~

▪︎$18x [ - 9x³ - × + x² - × + 6 - × - 5x ]$

▪︎$18x - 9x³ - x² - 6 + 5x$

▪︎$18x + 5x - 9x³ - x² - 6$

☆ After adding the common term~

▪︎$23x - 9x³ - x² - 6$

$\huge\pink{Their \ \ Solution = 23x - 9x³ - x² - 6}$

Answer:-

Hence, The solution of the : 18x - [ 5x³ + 3x² - { 2x² - ( 6 - 2x - x³ ) - 5x³ } - 3x ] = 23x - 9x³ - x² - 6.

:)