Question

18y³ - 33y² + 2y + 5 factorise it by using factor theorem

Answer 1

Answer:-

18y³ - 33y² + 2y + 5

(3y+1) (3y-5) (2y-1)

y=-1/3 y=5/3 y=1/2

Answer 2

Step-by-step explanation:

$\mathbb\red{ \tiny A \scriptsize \: N \small \:S \large \: W \Large \:E \huge \: R}$

$\begin{array}{l}\dashrightarrow\displaystyle \rm 18 y^{3}-33 y^{2}+2 y+5 \\ \\ \displaystyle \rm \text{ Use the rational root theorem} \\ \\ \displaystyle \rm\[ =(2 y-1) \frac{18 y^{3}-33 y^{2}+2 y+5}{2 y-1} \] \\ \\ \[ \begin{array}{l}\displaystyle \rm\dashrightarrow \frac{18 y^{3}-33 y^{2}+2 y+5}{2 y-1}=9 y^{2}-12 y-5 \\ \\ \displaystyle \rm =(2 y-1)\left(9 y^{2}-12 y-5\right) \end{array} \] \\ \\\displaystyle \rm \text{ Factor }9 y^{2}-12 y-5: \quad(3 y+1)(3 y-5) \\ \\ \boxed{\red{\displaystyle \rm =(2 y-1)(3 y+1)(3 y-5)}} \end{array}$