Question

18years ago,a man was three times as old as his son.nowthe man is twice aa old as his sonn .the sun of the present ages of the man and his son is​

Answer 1

Answer:

son= 36 years old

father=108 years old

Step-by-step explanation:

let the age of father be 'x' and son be 'y'

3(x-18) = y-18

2x=y

3x-54 = 2x -18

3x-2x = 54-18 (transpose)

x = 36

2x = 2×36

= 72(son)

x+y= 72+36= 108 years (father)