Question

19.
10. The sum of a two-digit number and the number
obtained by reversing the order of its digits is 99. If
the digits differ by 3, find the number.
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Answer 1

Answer:

ab+ba=99

10a+b+10b+a=99

11a+11b=99

11(a+b)=99

a+b=9

a=9-b.......(1)

b-a=3(given)

b-(9-b)=3

b-9+b=3

2b-9=3

2b=3+9

2b=12

b=6....ans.

a=9-b

a=9-6

a=3..... ans.