19, 13, 7, 1, -5,…..Find the sum of the 12th term of this sequence.
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Answer:
Step-by-step explanation:
Given : a = 19 , d = -6 and n = 12
Sum of n terms of a ap is
n/2 ( 2a + (n-1)d)
12/2 ( 2 × 19 + ( 12-1) (-6))
-168 is the answer
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