Question

19.250 families with 2 children are selected randomly and following data were
obtained
Number of
1
sons in tamil
Number of
125
50
families
Find the probability of families having
a) 2 sons (3/10)
bison (1/3)
no son
20 One number is choosen at random from numbers 1 to 100. Find the probability
that it is divisible by 4 or 6​

Answer 1

ANSWER

(i) Number of families having 2 girls =475

Total families =475+814+211=1500     

P(2 girls) =Total families475

=1500475=6019

(ii) P(1 girl)=1500814=750407

(iii) P(No girl) =1500211

Sum of all these probabilities 

=6019+750407+1500211

=1500475+814+211

=15001500=1

Sum of these probabilities =1