Question

-19*[4+(-2)=-19*4+(-19)*x solv this que​

Answer 1

Answer:

Given equation, x

5

+5x

4

−20x

2

−19x−2=0

Consider f(x)=x

5

+5x

4

−20x

2

−19x−2

Then, f(2)=−8 and f(3)=409

Since the signs of f(2) and f(3) are opposite, f(x) must cross x-axis atleast once in the interval (2,3).

∴f(x)=0 must have a root between 2 and 3

Similarly, f(−4)=10 and f(−5)=−407.

Since the signs of f(−4) and f(−5) are different, f(x)=0 must have one root between −4 and −5.

Step-by-step explanation:

hope I help you

Answer 2

Answer:

$- 19 \times 4 + ( - 2) = ( - 19) \times 4 + ( - 19) \times x \\ \\ = > - 76 - 2 = - 76 - 19 \times x \\ \\ = > - 78 + 76 = - 19x \\ \\ = > - 2 = - 19x \\ \\ = > 19x = 2( - \: and \: - \: cancelled) \\ \\ > x = \frac{2}{19}$

〰 hope it helps u 〰