19+7/2-5
add two pairs of brackets to this equation so that it =2
How?
/= divide sign there are no fractions involved
Answers
Answer:
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Answer:
y=There are at least several statements using the digits 19,7,3, and 2 and two pairs of brackets/parentheses that produce the result 2
PREMISES
y=19+7÷2–3=2
ASSUMPTIONS
Let the expression y=19+7÷2–3 be rewritten as y(1), y(2), y(3), y(4) and so forth
CALCULATIONS
y=19+7÷2–3 with two sets of brackets/parentheses becomes
y(1)=19-[(7×2)+3]
y=19-[(14)+3]
y=19-17
y=
2
y(2)=(19–3)-(7×2)
y=16–14
y=
2
y(3)=[(19–7)/3]-2
y=(12/3)-2
y=4–2
y=
2
y(4)=[(19–7)/3]/2
y=(12/3)/2
y=4/2
y=
2
y(5)=[(7×3)-19]/2^0
y=(21–19)/2^0
y=2/1
y=
2
Step-by-step explanation:
y=There are at least several statements using the digits 19,7,3, and 2 and two pairs of brackets/parentheses that produce the result 2
PREMISES
y=19+7÷2–3=2
ASSUMPTIONS
Let the expression y=19+7÷2–3 be rewritten as y(1), y(2), y(3), y(4) and so forth
CALCULATIONS
y=19+7÷2–3 with two sets of brackets/parentheses becomes
y(1)=19-[(7×2)+3]
y=19-[(14)+3]
y=19-17
y=
2
y(2)=(19–3)-(7×2)
y=16–14
y=
2
y(3)=[(19–7)/3]-2
y=(12/3)-2
y=4–2
y=
2
y(4)=[(19–7)/3]/2
y=(12/3)/2
y=4/2
y=
2
y(5)=[(7×3)-19]/2^0
y=(21–19)/2^0
y=2/1
y=
2