Math, asked by ilaniotyeptho20, 5 months ago

( 19×9+31×10+32×11)/(233•25×2-50)​

Answers

Answered by Jaswindar9199
0

Answer is 2

GIVEN:- ( 19×9+31×10+32×11)/(233.25×2-50)

TO FIND:- value

SOLUTION:-

According to the sum, 19×9+31×10+32×11 is divided by 233.25×2-50

First, we'll solve 19×9+31×10+32×11,

19×9+31×10+32×11 \\  = 171 + 310 + 352 \\  = 833

Secondly, we'll solve 233.25×2-50

233.25×2-50 \\  = 466.5 - 50 \\  = 416.5

According to the question

 \frac{19×9+31×10+32×11}{233.25×2-50}  \\

By putting in the values and dividing according to the sum

 =  \frac{833}{416.5}  \\  = 2

Hence, the answer is 2

#SPJ2

Answered by syed2020ashaels
0

Answer:

The answer to the given question is 2

Step-by-step explanation:

Given :

( 19×9+31×10+32×11)/(233•25×2-50)

we have to solve the given expression.

The exact form of the expression is

 \frac{(19 \times 9 + 31 \times 10 + 32 \times 11)}{(233.25 \times 2 - 50)}

we can solve this problem by using the BODMAS method.

BODMAS stands for Brackets, orders of powers, Division, Multiplication, Addition, and Subtraction.

First, we have to solve the numerator value

(19 \times 9 + 31 \times 10 + 32 \times 11)

On applying the bodmas method, the first multiplication operation should be performed

171 + 310 + 352

After multiplication addition should be performed

833

Next, we can solve the denominator

233.25 \times 2 - 50 \\

first multiplication then subtraction, we get the value as

466.5 - 50

On subtracting we get the values as

416.50

According to the question, we have to substitute the values

 \frac{(19 \times 9 + 31 \times 10 + 32 \times 11)}{(233.25 \times 2 - 50)}  =  \frac{833}{416.5}

On dividing, we get the value as

 \frac{833}{416.5}  = 2

The answer is 2.

Therefore, the final answer to the given question is 2

#spj5

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