19. A 2.24L cylinder of oxygen at N.T.P. is found to develop a leakage. When the leakage was plugged the
pressure dropped to 570 mm of Hg. The number of moles of gas that escaped will be
(A) 0.025
(B) 0.050
(C) 0.075
(D) 0.09
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Answer:
Explanation:
Original pressure of Hg= 760
drop in pressure= 570
change in pressure= 760-570= 190mm
= 190/760 atm
PV= nRT
n = P V/ RT
= 190 x 2.24/ 760 x 0.821 x 273
= 0.0249 moles
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