Question

19). A alone can do a work in 16 days. B alone can do same work in 32 days. C alone can do the
sarre work in 48 days. They all started working together and after 4 days, C left the work. B also
completely left the work but just two days before the completion of work.
a) What is the total no of days required to complete the whole work?
b). For how many days did B work?​

Answer 1

Answer:

LCM of 16,32,48 to find total work

so, LCM is 96

and then we divide the total work by each no to find one day work so, 16 = 6 , 32 = 3 , 48 = 2

work done by a, b, c in four days, 4*11=44

left work 96-44=52

Thanks and use your mind to do

because when we strong our think then question is very easy to do