Question

19)
A bag contains 8 red, 15 green, 7 blue balls. If one ball is chosen at random. what is
the probability of choosing
a red ball
a green ball
a blue ball
iin​

Answer 1

Answer:

ans is :(a) 8/30 (b) 15/30 (c) 7/30

Answer 2

$\huge\fbox\red{\fbox\orange{Solutions:-}}$

$\fbox\red{\fbox\red{Given:-}}$

$\red{red \: balls = 8} \\ \green{green \: balls = 15} \\ \blue{blue \: balls = 7}$

$\fbox\red{\fbox\pink{To find:-}}$

$\orange{probability \: of \: }\\ \red{red \: balls} \\ \green{green \: balls} \\ \blue{blue \: balls}$

$\fbox\red{\fbox\red{By the problem:-}}$

$\red{p(red \: balls) = > \frac{8}{30} } \\ \green{ p(green \: balls) = > \frac{15}{30} } \\ \blue{ p(blue \: balls) = > \frac{7}{15} }$