Question

- 19. A bar magnet of length 10cm and pole strength
20A-m is deflected through 30° from the magnetic
meridian. If earth's horizontal component field is
320
A/m. The moment of the deflecting couple is
470
1) 160x10-'Nm
2) 32078 X10 Nm
A) 320x10-Nm
4) 1601 X10-7Nm​

Answer 1

Given:

The length of bar magnet L= 10 cm

The pole strength is M= 20A-m

The deflected angle is 30°

The earth's horizontal component B= 320A/ m

To find:

The moment of the deflecting couple is

Solution:

The formula of the torque is

τ=MBsinФ

τ=MlBsinФ

Putting above value

τ= 20×0.1×320×sin(30)

=320 Nm

So the option 3 is correct

Answer 2

Answer:

this is the answer for this question