Question

19. A block of mass m is released on a smooth inclined
plane of inclination with the horizontal. The force
exerted by the plane on the block has a magnitude
with diagram​

Answer 1

Answer:

nothing

Explanation:

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Answer 2

Explanation:

Ma cos0= mg sin0

a=g tan0

N= mg cos0 + ma sin0

N= mg cos0 + m (gtan0) sin0

N= mg cos0 + mg (sin0 / cos0) sin0

N= mg cos²0 + mgsin²0/ cos0

= mg cos0 (cos²0 + sin²0)

= mg / cos0

Block of mass m is released on the smooth inclined plane with the inclination theta horizontal to force exerted by plane on the block