Question

19. A body is thrown up with an initial velocity u and
covers a maximum height of h, then h is equal to
(a) u²/2g
(b) u/2g
(c) 2ug
(d)2u²/g​

Answer 1

v² = u² + 2gh

here,

v = 0 (final velocity)

h = u²/2g

Answer 2

Answer:

v² = u² + 2gh

here,

v = 0 (final velocity)

h = u²/2g