19. A box contains some are triangles, squares and circle shape card. If we drawn a
card what is the probability of getting
(1) Triangles
(ii) Circle
(iii) Not square
Answers
Step-by-step explanation:
No. of cards in the bag =44
No. of cards with circles =24
No. of cards with blue circles =9
No. of cards with green circles =24−9=15
No. of cards with squares =20
No. of cards with blue squares =11
No. of cards with green squares =9
Solution(i):
Let E be the event of drawing a square card from the bag
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
44
20
=
11
5
Therefore, the Probability that the square card is drawn =
11
5
Solution(ii):
Let E be the event of drawing a green card from the bag
No. of green cards =15+9=24
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
44
24
=
11
6
Therefore, the Probability that the green card is drawn =
11
6
Solution(iii):
Let E be the event of drawing a blue circle from the bag
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
44
9
Therefore, the Probability that the blue circle is drawn =
44
9
Solution(iii):
Let E be the event of drawing a green square from the bag
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
44
9
Therefore, the Probability that the green square is drawn =
44
9