Question

19. (a) Calculate the mass of water formed, when 10g of hydrogen is allowed to react with 10 g of oxygen.
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Answer 1

Answer:

2H

2

+O

2

→2H

2

O

10 g of hydrogen (molar mass 2 g/mol) =

2 g/mol

10 g

= 5 mol

64 of oxygen (molar mass 32 g/mol) =

32 g/mol

64 g

= 2 mol

As per the balanced chemical equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water.

2 moles of oxygen will react with 2×2=4 moles of hydrogen to form 4 moles of water.

Here, oxygen is the limiting reagent and hydrogen is the excess reagent.