Math, asked by sanjeevkrishna1976, 2 days ago

19. A father is 30 years older than his son. In 12 years, the man will be three times as old as his son. Find their present ages.​

Answers

Answered by akshitakumar65
1

Step-by-step explanation:

Let the present age of the son be x years

Then father's age will be (x+30) years

Given after 12 years father will be three times as old as his son

Therefore,

(x+12)3=x+30+12

3x+36=x+42

3x−x=42−36

2x=6

x=3

x+30=3+30=33

So, the present age of son is 3 years and present age of the father is 33 years

Answered by aditimi2010
0

let the son's present age be x

let father's present age be x+30

"after 12 years-

son's age. =x+12

father's age=x+30+12

=x+42

according to question-

x+42=3(x+12)

x+42=3x+36

42-36=3x-x

6=2x

x=6/2

x=3

son's present age=3years

father's present age=3+30=33years

Similar questions