Question

19. A force F acting on a particle varies with the
position x as shown in the figure. The work done
by this force in displacing the particle from
x=-- 2 m to x = 0 is
F(N)= 10, -10
x(m) = 2, -2

(a) - 10J
(b) + 5J
(C) - 20J
(d) + 400​

Answer 1

Answer:

l think c one is right answer