Question

19. A force is inclined at 60° to the horizontal. If its
rectangular component in the horizontal direction is
50 N, then magnitude of the vertical component of force
is approximately
(a) 87.987 N
(b) 86.667 N
(c) 87.608N
(d) 86.602N​

Answer 1

Answer:

c ) - 87 N is the answer ,

please let me know if my answer is wrong.

Answer 2

Answer:

d) 86.602 N

Explanation:

x cos 60° = 50

x = 100 N

x cos 30° = 100 cos 30° = 50√3 = 86.602 N.