Question

19. A lens of focal length 12 cm forms an erect image, three times the size of the object.

The distance between the object and image is:

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Answer 1

Answer:

DISTANCE BETWEEN THE OBJECT AND THE IMAGE = 16 CM

Explanation:

16 cm

Magnification, m = v/u

3 = v/u

⇒ v = 3u

Lens formula : 1/v – 1/u = 1/f

1/3u = 1/u = 1/12

-2/3u = 1/12

⇒ u = -8 cm

V = 3 × (-8) = -24

Distance between object and image = u – v = -8 – (-24) = -8 + 24 = 16 cm