Question

19. A load of 100 kg is pulled up by 5 m. Calculate the work done. (g = 9.8 m/s2)


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Answer 1

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Answer 2

Step-by-step explanation:

${ \huge{ \green{ \underline{ \frak{Given}}}}}{{ \huge{ \green{ \frak{ \colon}}}}}$

${ \red{ \sf{➢Mass(m) = 100 \: kg}}}$

${ \blue{ \sf{➢Dispcement (d)= 5 \: m}}}$

${ \orange{ \sf{➢g = 9.8 \: m s {}^{2} }}}$

${ \large{ \purple{\underline{ \boxed{ \sf{✭Work \: \: done (Vertical \: \: direction) = m\times g \times h}}}}}}$

${ \large{ \pink{ \therefore{ \sf{Work \: \: done = 100 \times 5 \times 9.8 =}}}}} \: { \large{ \red{ \boxed{ \sf{4900 \: Joule}}}}} \: { \large{ \pink{ \sf{Ans.}}}}$