Question

19. A mixture consists of 45 % sand, 36% gravel and rest cement. Find the weight of
mixture which contains 12.5 kg wt of sand. Also determine the weight of mixture that will
contain 4 kg wt of cement.
​

Answer 1

Answer:

Let the mixture be 100%

Quantity of sand in the mixture =

11

500

%

Quantity of gravel in the mixture =

11

400

%

Quantity of Cement in the mixture =100%−

11

500

%−

11

400

%

⇒

11

1100÷500−400

%

⇒

11

200

%

Let xKg of mixture contain 12.5Kg of sand

But 100% of mixture contains

11

500

% of sand

⇒

100%

x

=

11

500

%

12.5

⇒x=

500%

12.5×100%

×11Kg

=2.5×11kg

=27.5Kg

let yKg of mixture contain 4Kg of cement

But 100% of mixture contain

11

200

% discount

⇒

100%

y

=

11

200

%

4

y=22Kg

Answer 2

Step-by-step explanation:

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