Question

19 A shell of mass 0.020 kg is fired by a gun of mass 100 kg. If the muzzle speed of the
5.20 A batsman deflects a ball by an angle of 45° without changing its initial speed which is
K8
collide and rebound with the same speed. What is the impulse imparted to each ball due
shell is 80 m s, what is the recoil speed of the gun?
equal to 54 km/h. What is the impulse imparted to the ball ? (Mass of the ball is 0.15 kg.)
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Answer 1

Answer:

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Explanation:

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Answer 2

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recoil velocity of Gun=0.016m/s

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Mass of gun M = 100kg

mass of shell  m = 0.020kg

Velocity of shell  v = 80m/s

Recoil velocity of Gun V=?

initial velocities of both gun and shell will be zero

so, the initial momentum of the system will be zero.

According to the law of conservation of momentum,

Initial momentum = Final momentum

so,

0=mv-MV

∴v=mv/M

=0.020×80/100

=0.016 m/s

∴recoil velocity of Gun=0.016m/s