Physics, asked by gayatribhatt8065, 6 months ago


19. (a) The radius of a capillary tube is 0.025 mm.
It is held vertically in a liquid whose density is
0.8 x 10 kg m-%, surface tension is 3.0 x 10-2 Nm
and for which the cosine of the angle of contact is 0.3.
Determine the height up to which the liquid will rise
in the tube. Take g
10 ms
-2

(b) If the capillary is taken down in water slowly until
its upper end comes in level of water, will the water
come out from this end ?

Answers

Answered by shristi6018
0

Answer:

I send your answer after sometime because I am busy

Answered by BPTejaswini
0

Answer:

a)

h=2T×cos teta/density×g×r

T=3×10^-2Nm^-1

cos teta=0.3

g=10ms^-2

density=0.8×10^3kgm^-3

r=0.0

h=2×3×10^-2×0.3 /(0.8×10^3)×(0.025×10^-3 )×10

h=1.8×10^-2/2×10^-1

h=0.9×10^-1

h=0.09m

h=9cm

b)No

Similar questions