19.
A thin uniform rod of length I, and mass m is
uniformly charged with a total charge q. The rod
1
is rotated about a point at a distance
from
3
midpoint of the rod. The magnitude of the
magnetic moment of the rod, if the angular
velocity is o is e
qo/2
72
72
me
7qo/
(3)
3x9 (4)
36
9
7
My IW (2)
90/2
90/2
20.
Attachments:
Answers
Answered by
3
Answer:
Consider a small element dx at a distance x from the pivot.
Charge on element dq=
l
q
dx
The rod sweeps a circle of radius
2
l
Charge dq rotating at frequency f will give rise to current di=dq×f=
l
q
fdx
Magnetic moment of this element dx is dμ=di×A=
l
q
fdx×πx
2
where A is the area of the circle of radius x.
∴μ=∫
0
l
dμ=∫
−l/2
l/2
l
q
f×πx
2
dx=
l
πqf
⎝
⎜
⎜
⎜
⎜
⎛
3
(
2
l
)
3
−
3
(
2
−l
)
3
⎠
⎟
⎟
⎟
⎟
⎞
=
12
πqfl
2
Explanation:
hope it is helpful
Answered by
0
can u pls tell me name of this book...is this akash volume book Or any study material
Similar questions