19. Arjun has some 1-rupee coins and some 2-rupee coins in his piggy-bank. The number of 1-rupee coins is thrice that of 2-rupee coins. If the total value of these coins is 50, find the number coins of each denomination.
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Answers
Answer:
Let the total number of coins be 12X.
Then,
Number of Rs.5 coins = 3X
Number of Rs.2 coins = 4X
Number of Re.1 coins = 5X
Total value of :-
Rs.5 coins = 3X * 5 = 15X
Rs.2 coins = 4X * 2 = 8X
Re.1 coins = 5X * 1 = 5X
Given, total value of all coins = 224
Therefore,
15X + 8X + 5X = 224
28X = 224
X = 8
Total number of coins = 12X = 12 * 8 = 96
Number of,
Rs.5 coins = (3/12) * 96 = 24 coins
Rs.2 coins = (4/12) * 96 = 32 coins
Re.1 coins = (5/12) * 96 = 40 coins
(Given no. of Rs.5, Rs.2, and Re.1 coins are in the ratio of 3:4:5)
Final Answer : The boy has 40 Re.1 coins.
Let's cross verify the answer once.
(24*5) + (32*2) + (40*1)
= 120 + 64 + 40
= 224 = Value given in the question.
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Let —
value of coins of 2 = x = 2 multiply x = 2x
value of coins of 1 = 3x = 3x multiply 1 = 3x
value of total coins = ₹50
Ac. to que. —
2x + 3x = 50
5x = 50
x = 50/5
x = 10
no of coins of 2 = x = 10
no of coins of 1 = 3x = 3 x 10 = 30