Math, asked by vikashbeswal, 5 months ago

19. Arjun has some 1-rupee coins and some 2-rupee coins in his piggy-bank. The number of 1-rupee coins is thrice that of 2-rupee coins. If the total value of these coins is 50, find the number coins of each denomination.
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Answers

Answered by tausiquestm
0

Answer:

Let the total number of coins be 12X.

Then,

Number of Rs.5 coins = 3X

Number of Rs.2 coins = 4X

Number of Re.1 coins = 5X

Total value of :-

Rs.5 coins = 3X * 5 = 15X

Rs.2 coins = 4X * 2 = 8X

Re.1 coins = 5X * 1 = 5X

Given, total value of all coins = 224

Therefore,

15X + 8X + 5X = 224

28X = 224

X = 8

Total number of coins = 12X = 12 * 8 = 96

Number of,

Rs.5 coins = (3/12) * 96 = 24 coins

Rs.2 coins = (4/12) * 96 = 32 coins

Re.1 coins = (5/12) * 96 = 40 coins

(Given no. of Rs.5, Rs.2, and Re.1 coins are in the ratio of 3:4:5)

Final Answer : The boy has 40 Re.1 coins.

Let's cross verify the answer once.

(24*5) + (32*2) + (40*1)

= 120 + 64 + 40

= 224 = Value given in the question.

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Answered by Anonymous
5

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Let —

value of coins of 2 = x = 2 multiply x = 2x

value of coins of 1 = 3x = 3x multiply 1 = 3x

value of total coins = ₹50

Ac. to que. —

2x + 3x = 50

5x = 50

x = 50/5

x = 10

no of coins of 2 = x = 10

no of coins of 1 = 3x = 3 x 10 = 30

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