Math, asked by nitinwaidande961, 1 day ago

19 At a certain college, the economics club plans to sell T-shirts as a fund raiser. "e president of the club estimates that when the price of a T-shirt is $18, there will be 60 T-shirts sold, and for every $1 the price of the shirt is reduced, 10 additional T-shirts will be sold. Based on this estimate, what is the maximum amount of revenue, in dollars, the club can earn from T-shirt sales? (Revenue equals price times number sold. Disregard the $ sign when gridding your answer.)

Answers

Answered by amitnrw
3

Given :  When the price of a T-shirt is $18, there will be 60 T-shirts sold,

For every $1 the price of the shirt is reduced, 10 additional T-shirts will be sold.

To Find : Maximum amount of revenue, in dollars, the club can earn from T-shirt sales

Solution:

Price of T shirt  = 18  $

Number of T Shirts sold = 60

Revenue = 18 * 60  = 1080 $

For every $1 the price of the shirt is reduced, 10 additional T-shirts will be sold.

Let sat price of T Shirts reduces by x $ then increase in sell = 10x

T shirts price  = 18 - x   $

T shirts sold = 60 + 10x

Revenue   R(x) = (18 - x)(60 + 10x)

R(x) = (18 - x)(60 + 10x)

R'(x) = (18 - x) (10)  + (-1)(60 + 10x)

= 180 - 10x  -60 - 10x

= 120 - 20x

R'(x) = 0

=> 120 - 20x = 0

=> x = 6

R''(x) = - 20  < 0

Hence Maximum revenue when x = 6

R(x) = (18 - x)(60 + 10x)

x = 6

=> R(6) = (18 - 6) (60 + 10 *6)

= (12)(120)

= 1440  $

Maximum revenue =  1440  $

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