19 cards numbered 1, 2, 3....... 19 are put in a box one person draws one card from box find the probability the number on the card is (1) even (2) prime (3)divisible by 3 (4)divisible by 3 and 2 both.
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Answered by
3
HERE IS YOUR ANSWER
1). the even numbers are 2,4,6,8,10,12,14,16,18
even numbers = 9
p( even number) = 9/19
2). the prime numbers are 2,3,5,7,11,13,17,19
prime numbers = 8
p(prime number) = 8/19
3) the numbers which are divisible by 3 are 3,6,9,12,15,18
the numbers which are divisible by 3 = 6
p(divisible by 3) = 6/19
4) the numbers which are divisible by 3 and 2 both are 6,12,18
the numbers which are divisible by 3 and 2 both = 3
p( divisible by 3 and 2 both) = 3/19
HOPE THE ANSWERS ARE CORRECT
1). the even numbers are 2,4,6,8,10,12,14,16,18
even numbers = 9
p( even number) = 9/19
2). the prime numbers are 2,3,5,7,11,13,17,19
prime numbers = 8
p(prime number) = 8/19
3) the numbers which are divisible by 3 are 3,6,9,12,15,18
the numbers which are divisible by 3 = 6
p(divisible by 3) = 6/19
4) the numbers which are divisible by 3 and 2 both are 6,12,18
the numbers which are divisible by 3 and 2 both = 3
p( divisible by 3 and 2 both) = 3/19
HOPE THE ANSWERS ARE CORRECT
Answered by
0
Answer:
1) even - 2,4,6,8,10,12,14,16,18 = 9/19
2)prime - 2,3,5,7,11 = 8/19
3)divisible by 3 - 3,6,9,12,15,18 = 6/19
4) divisible by 3 and 2 both - 6,12,18 = 3/19
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