Math, asked by nunu1374, 1 year ago

19 cards numbered 1, 2, 3....... 19 are put in a box one person draws one card from box find the probability the number on the card is (1) even (2) prime (3)divisible by 3 (4)divisible by 3 and 2 both.

Answers

Answered by swamynathanvp435
3
HERE IS YOUR ANSWER

1). the even numbers are 2,4,6,8,10,12,14,16,18

even numbers = 9

p( even number) = 9/19

2). the prime numbers are 2,3,5,7,11,13,17,19

prime numbers = 8

p(prime number) = 8/19

3) the numbers which are divisible by 3 are 3,6,9,12,15,18

the numbers which are divisible by 3 = 6

p(divisible by 3) = 6/19

4) the numbers which are divisible by 3 and 2 both are 6,12,18

the numbers which are divisible by 3 and 2 both = 3

p( divisible by 3 and 2 both) = 3/19


HOPE THE ANSWERS ARE CORRECT
Answered by arushisingh150148
0

Answer:

1) even - 2,4,6,8,10,12,14,16,18 = 9/19

2)prime - 2,3,5,7,11 = 8/19

3)divisible by 3 - 3,6,9,12,15,18 = 6/19

4) divisible by 3 and 2 both - 6,12,18 = 3/19

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