Question

19. Case Study Based -3 Our maths teacher knows Yoga. She asked Nitya to show yoga postures. She made marks on angles. She showed acute, obtuse and right angle through yoga Postures.
The exterior angle of a triangle is equal to the
i) sum of the two interior opposite angles i
ii) difference of two interior angles
iii) sum of the three interior angles
iv) opposite of the interior angle

The value of m in the figure is
i) 94 degrees
ii) 214 °
(c) The value of x in the figure is i) 7° ii) 9° iii)84^ 0 The value of 'y' in the figure is i) |23^ ii) 41 ^ o iii) 45 ^ 0 ° 6 ^ 0 iv) 4 ^ 0 (a) ii) sum of the three interior angles opposite of the interior angle iv) overline m ^ 60° iv) 26 degrees (b) 154 degrees -1 0^ 4x (d) 3(y-15)^ W 58 degrees 44 degrees iv)43^ Two gates consist of vertical posts, horizontal struts and diagonal beams. The angle 'a' from the figure is i)140° ii) 40 ^ 0 ii)120^ iv)50^ 0 (e) 40 degrees​

Answer 1

Step-by-step explanation:

The exterior angle of a triangle is equal to the

i) sum of the two interior opposite angles

The value of m in the figure is

i) 94 degrees

c) The value of x in the figure is i) 7°

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Answer 2

Question :- The value of m in the figure is :-

(i) 94°

(ii) 214°

(iii) 84°

(iv) 26°

Solution :-

we know that,

• Exterior angle of a ∆ is equal to sum of two opposite interior angles .

so,

→ m° + 60° = 154°

→ m° = 154° - 60°

→ m° = 94° (Option i) (Ans.)

Hence, value of m in the figure is 94° .

Learn more :-

In ABC, AD is angle bisector,

angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

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