Question

19.

Cube of a natural number will never end with the digit

(a) 0

(b) 1

(c) 3

(d) none of these​

Answer 1

Answer is 3

2^2 =4 9^2 =81 10^2= 100

Answer 2

Answer:

None of these

Step-by-step explanation:

$(10)^{2} = 1000$

$(11)^{2} = 1331$

$(7)^{3} = 343$

So the answer is none of the above