Math, asked by dakpeakom99556, 7 hours ago

19. During the lockdown period, people were very puzzled and they decided to play some game. Firstly, they collect 17 cards and write the number 1 to 17 and them in a box. People make a bet for the chances of drawing the number either the prime, odd or even numbers etc.

(a) Find the probability that the number on the card is an odd number.
(i) 9 /17 (ii) 8 /17 (iii) 6 /17 (iv) 5 /17
(b) Find the probability that the number on the card is a prime number.
(i) 7 /17 (ii) 9/ 17 (iii) 8 /17 . (iv) 5 /17
(c) Find the probability that the number on the card is divisible by 2 and 3 both.
(i) 2/ 17 (ii) 3 /17 (iii) 4 /17 (iv) 5/ 17
(d) Find the probability that the number on the card is a multiple of 3 or 5.
(i) 7/ 17 (ii) 5/ 17 (iii) 9 /17 (iv) 2/ 17
(e) An event having only one outcome of the random experiment is called
i. Elementary Event ii. Compound Event iii. Equally Likely iv. None of the above​

Answers

Answered by neharanchi1993
7

Answer:

a) 9/17

b) 7/17

c) 2/17

d) 7/17

e) elementary event

Answered by tiwariakdi
1

a) Option (i) 9/17 is correct.

b) Option (i) 7/17 is correct.

c) Option (ii) 3/17 is correct.

d) Option (i) 7/17 is correct.

e) Option (i) Elementary Event is correct.

(a) The probability that the number on the card is an odd number is given by the number of odd numbers between 1 and 17 divided by the total number of possible outcomes, which is 17. There are 9 odd numbers between 1 and 17, so the probability is:

(i) 9/17

(b) The probability that the number on the card is a prime number is given by the number of prime numbers between 1 and 17 divided by the total number of possible outcomes, which is 17. There are 7 prime numbers between 1 and 17, so the probability is:

(i) 7/17

(c) The probability that the number on the card is divisible by 2 and 3 both is given by the number of numbers between 1 and 17 that are divisible by both 2 and 3, divided by the total number of possible outcomes, which is 17. There are two such numbers, which are 6 and 12, so the probability is:

(ii) 3/17

(d) The probability that the number on the card is a multiple of 3 or 5 is given by the number of numbers between 1 and 17 that are multiples of either 3 or 5, or both, divided by the total number of possible outcomes, which is 17. These numbers are 3, 5, 6, 9, 10, 12, and 15, so the probability is:

(i) 7/17

(e) An event having only one outcome of the random experiment is called an elementary event.

Therefore, the answer is (i) Elementary Event.

for such more question on probability

https://brainly.in/question/21113326

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