Question

19. Electric current through resistance 4 N, in the given circuit is:
12 V
1
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21 9
11 + 12
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112
Eictor
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4 Ω
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12
122
12
(a) OA
(6) 0.5 A
(c) 12/7 A
(d) 2/7 A

Answer 1

Answer:

Explanation:

Solution

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Verified by Toppr

(i) R=6+3=9Ω

V=4V

I=

R

V

​

=

9

4

​

=0.45A

(ii) 12 ohm and 3 ohm are in series

R=12+3=15Ω

I=

R

V

​

=

15

4

​

=0.27A

p.d across 12 ohms= IR=0.27×12=3.24V