Question

19. Expand (a+b+c)2. answer ​

Answer 1

Answer:

a2+b2+c2+3ab+3bc+3ac

Step-by-step explanation:

(a+b+c) 2=(a+b+c)(a+b+c)

=a2+ab+ac+ab+b2+bc+ac+bc+c2

=a2+b2+c2+3ab+3bc+3ac

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Answer 2

$\Huge\bf\maltese{\underline{\green{Answer°᭄}}}\maltese$

$\implies$$\large\bf{\underline{\red{VERIFIED✔}}}$

$(a+b-c)^2 \\ Can \: be expressed \: as \\ =(a+b-c) \times (a+b-c) \\ On \: expansion \: of \: the \: above \: expression \\ =a(a+b-c)+b(a+b-c)-c(a+b-c) \\=a^2+ab-ac+ba+b^2-bc-ca-cb+c^2 \\Rearrange \: the \: above \: equation \\=a^2+b^2+c^2+ab+ba-ac-ca-bc-cb \\Rearrange \: by \: commutative \: property \\=a^2+b^2+c^2+ab+ab-ac-ac-bc-bc \\=a^2+b^2+c^2+2ab-2ac-2bc \\ On \: taking \: out \: the \: common \: terms, \: the \\ expansion \: results \: in \: the \: final \: answer. \\ =a^2+b^2+c^2+2(ab-ac-bc)$

$\boxed{I \:Hope\: it's \:Helpful}$

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