Question

19. Find out three numbers such that the
product of the first and the second is
24, that of the second and the third is
48, and that of the first and the third
is 32.

Answer 1

Answer:

Suppose the numbers are X, Y, Z

According to given condition

XY=24---(1)

YZ=48---(2)

ZA=32---(3)

from 1,

Y=24/a----(4)

put 4 in 2

(24/X)Z=48

24Z=48X

Z=48X/24

Z=2X----(5)

put 5 in 3

2Xx=32

X=16

X=4

put a=4 in 1

4y=24

y=24/4

y=6

put y=6 in 5

Z=2*4

z=8

so, the numbers are 4, 6, and 8

then product of 4*6=24

and 6*8=48

and 8*4=32

Step-by-step explanation: