Question

19. Find product of(4a-2b-3c) and(4a-2b-
3c).

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Answer 1

Answer:

$(4a - 2b - 3c)(4a - 2b - 3c)$

${(4a - 2b - 3c)}^{2}$

${(x + y + z)}^{2} = {x}^{2} + {y}^{2} + {z}^{2} + 2xy + 2xz + 2yz$

${(4a)}^{2} + {(2b)}^{2} + {(3c)}^{2} + 2(4a)( - 2b) + 2( - 2b)( - 3c) + 2(4a)( - 3c)$

$16 {a}^{2} + 4 {b}^{2} + 9 {c}^{2} - 16ab + 12bc - 24ac$

Step-by-step explanation:

Hope it helps you out.......