Question

19. Find the 16th term of an AP, whose first term is - root 2 and common difference is 1 by root 2

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Answer 1

Answer:

Answer is in the above picture

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Answer 2

Answer:

13

Step-by-step explanation:

given :-

a = -√2

d = 1/√2

find out :-

T16 =?

as we know that

tn = a+(n-1)d

so

T16 = -√2+(16-1)1/√2

=> -√2+15/√2

lcm is √2

so

-2+15

= 13 ans